Online Mathematics and Chemistry Help: 10.00 mL of vinegar (mass=10.05 g) requires 14.77 mL of 0.4926 M NaOH to reach the end point. Calculate the molarity and mass percent of the acetic acid in the vinegar.

Sunday 10 July 2011

10.00 mL of vinegar (mass=10.05 g) requires 14.77 mL of 0.4926 M NaOH to reach the end point. Calculate the molarity and mass percent of the acetic acid in the vinegar.

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